7. Answer the following

i. HCl is added to a hydrocarbon ‘A’ (C4H8) to give a compound ‘B’ which on hydrolysis with aqueous alkali forms tertiary alcohol ‘C’ (C4H10O). Identify ‘A’ , ‘B’ and ‘C’.

Answer:-
Chemical Equation

\[ \begin{array}{cc} \ce{CH3}\phantom{..............................}\ce{CH3}\phantom{.............................}\ce{CH3}\phantom{}\\ |\phantom{..................................}|\phantom{.................................}|\\ \ce{\underset{\text{2-Methylprop-1-ene}}{H3C - C = CH2} + HCl ->[Markovnikov][rule] H3C - C - CH3->[KOH(aq.) Hydrolysis][\triangle] H3C - C - CH3}\\ \ce{(C4H8)}\phantom{...............................}|\phantom{.................................}|\phantom{...}\\ \phantom{..............}\ce{(A)}\phantom{.......................}\ce{\underset{\text{2-Chloro-2-methylpropane (B)}}{Cl}}\phantom{.........}\ce{\underset{\text{2-Hydroxy-2-methylpropane (C4H10O)(C)}}{OH}}\\ \end{array} \]

10 Halogen Derivative Page 233