chapter 6. CHEMICAL KINETICS class 12 chemistry textbook solution

    4. Solve

    vii. A first order reaction takes 40 minutes for 30% decomposition. Calculate its half life. (77.66 min)

    Answer:- 

    Given:

    [A]0 = 100%, [A]t = 100 - 30 = 70%, t = 40 min

    To find:

    Half-life of reaction (t1/2)

    Formula:

    k = 2.303/t * log10[A]0/[A]t

    Calculation:

    Substituting these values into the formula:

    k = 2.303/40 min * log10 100/70

    = 2.303/40 min * log10 1.429

    = 2.303/40 min * 0.155

    = 0.008924 min-1

    t1/2 = 0.693/k = 0.693/(0.008924 min-1) = 77.66 min

    The half-life of the reaction is 77.66 min.

    Q 4.6
    Q 4.7
    Q 4.8

    chapter 6. CHEMICAL KINETICS class 12 chemistry textbook solution page 137