vii. Calculate the pH of 0.01 M sulphuric acid.

2. Answer the following in one sentence :

vii. Calculate the pH of 0.01 M sulphuric acid.

Answer:-

Sulfuric Acid pH Calculation

Given:

Concentration of sulfuric acid = 0.01 M

To find:

pH

Formula:

pH = \(-\log_{10}[H_3O^+]\)

Calculation:

Sulfuric acid (\(H_2SO_4\)) is a strong acid. It dissociates almost completely in water as:

\[H_2SO_{4(aq)} + 2H_2O_{(l)} \rightarrow 2H_3O^+_{(aq)} + SO^{2-}_{4(aq)}\]

Hence, \([H_3O^+] = 2 \times c = 2 \times 0.01 \, \text{M} = 2 \times 10^{-2} \, \text{M}\)

From formula (i),

pH = \(-\log_{10}[H_3O^+]\)

= \(-\log_{10}(2 \times 10^{-2})\)

= \(-\log_{10}2 - \log_{10}(10^{-2})\)

= \(2 - 0.3010\)

pH = 1.699

The pH of 0.01 M sulfuric acid is 1.699.