vii. Calculate the pH of 0.01 M sulphuric acid.
2. Answer the following in one sentence :
vii. Calculate the pH of 0.01 M sulphuric acid.
Answer:-
Sulfuric Acid pH Calculation
Given:
Concentration of sulfuric acid = 0.01 M
To find:
pH
Formula:
pH = \(-\log_{10}[H_3O^+]\)
Calculation:
Sulfuric acid (\(H_2SO_4\)) is a strong acid. It dissociates almost completely in water as:
\[H_2SO_{4(aq)} + 2H_2O_{(l)} \rightarrow 2H_3O^+_{(aq)} + SO^{2-}_{4(aq)}\]
Hence, \([H_3O^+] = 2 \times c = 2 \times 0.01 \, \text{M} = 2 \times 10^{-2} \, \text{M}\)
From formula (i),
pH = \(-\log_{10}[H_3O^+]\)
= \(-\log_{10}(2 \times 10^{-2})\)
= \(-\log_{10}2 - \log_{10}(10^{-2})\)
= \(2 - 0.3010\)
pH = 1.699
The pH of 0.01 M sulfuric acid is 1.699.