Chemical Thermodynamics Chapter 4 Chemistry Class 12 Textbook Solution

    1. Select the most apropriate option.

    vii. If the standard enthalpy of formation of methanol is -238.9 kJ mol-1 then entropy change of the surroundings will be
    a. -801.7 J K-1

    b. 801.7 J K-1
    c. 0.8017 J K-1

    d. -0.8017 J K-1

    Answer:- b. 801.7 J K-1

    Explanation:-
    \begin{align*} \text{Explanation:} \\ \text{For standard state, temperature} &= 298 \, \text{K} \\ \Delta S_{\text{surr}} &= -\frac{\Delta H}{T} = -\frac{-238.9 \, \text{kJ}}{298 \, \text{K}} \\ &= +0.8017 \, \text{kJ} \, \text{K}^{-1} \\ &= 801.7 \, \text{J} \, \text{K}^{-1} \end{align*}
    Q1.6
    Q 1.7
    Q 1.8

    Chemical Thermodynamics Chapter 4 Chemistry Class 12 Textbook Solution