Chemical Thermodynamics Chapter 4 Chemistry Class 12 Textbook Solution
4. Answer the following questions.
xv. When 6.0 g of O2 reacts with CIF as per 2Cl F(g) + O2(g)→ Cl2O(g) + OF2(g) The enthalpy change is 38.55 kJ. What is standard enthalpy of the reaction ?
**Given:**
Enthalpy change for a given mass = 38.55 kJ
Mass of O2 = 6.0 g
**To find:**
Standard enthalpy of the given reaction
**Calculation:**
Number of moles of O2 = \(\frac{{\text{Mass of O}_2}}{{\text{Molar mass of O}_2}} = \frac{{6 \text{ g}}}{{32 \text{ g mol}^{-1}}} = 0.1875 \text{ mol}\)
The enthalpy change when 0.1875 moles of O2 reacts with ClF is 38.55 kJ.
\(\therefore\) Enthalpy change for 1 mole O2 = \(\frac{{38.55 \text{ kJ}}}{{0.1875}} = 205.6 \text{ kJ}\)
From the reaction, 2 moles of ClF react with 1 mole of O2.
So, the standard enthalpy of the reaction is \(+205.6 \text{ kJ}\).
Chemical Thermodynamics Chapter 4 Chemistry Class 12 Textbook Solution