7. Answer the following
ii. Complete the following reaction sequences by writing the structural formulae of the organic compounds ‘A’, ‘B’ and ‘C’ .
a)
\[\ce{2-Bromobutane->[Alc.KOH]A->[][Br2]B->[][NaNH2]C}\]
b)
\[\ce{Isopropyl alcohol ->[\triangle][PBr3] A ->[][NH3 excess] B}\] Answer:-
1)
\[\begin{array}{cc}
\phantom{.}\ce{Br}\phantom{................................................................}\ce{Br}\phantom{.............................................}\\
\phantom{...}|\phantom{..................................................................}|\phantom{................................................}\\
\ce{\underset{\text{2-Bromobutane}}{H3C - CH - CH2CH3}->[Alc.KOH][-KBr]\underset{\underset{(Major) (A)}{But-2-ene}}{H3C - CH = CH - CH3}->[Br2] H3C - CH - CH - CH3 ->[NaNH2][Double dehydrohalogen reaction] \underset{\text{But-2-yne (C)}}{H3C - C ≡ C-CH3}}\\
\phantom{.........}|\\
\phantom{................}\ce{\underset{\text{2,3-Dibromobutane (B)}}{Br}}
\end{array}\]
2) \phantom{.}\ce{Br}\phantom{................................................................}\ce{Br}\phantom{.............................................}\\
\phantom{...}|\phantom{..................................................................}|\phantom{................................................}\\
\ce{\underset{\text{2-Bromobutane}}{H3C - CH - CH2CH3}->[Alc.KOH][-KBr]\underset{\underset{(Major) (A)}{But-2-ene}}{H3C - CH = CH - CH3}->[Br2] H3C - CH - CH - CH3 ->[NaNH2][Double dehydrohalogen reaction] \underset{\text{But-2-yne (C)}}{H3C - C ≡ C-CH3}}\\
\phantom{.........}|\\
\phantom{................}\ce{\underset{\text{2,3-Dibromobutane (B)}}{Br}}
\end{array}\]
\[\begin{array}{cc}
\ce{H3C - CH = OH ->[\triangle][PBr3] H3C - CH - Br ->[NH3, Excess]H3C - CH - NH2}\\
|\phantom{......................}|\phantom{..........................}|\phantom{..}\\
\ce{\underset{\text{Isopropyl alcohol}}{CH3}\phantom{..............}}
\ce{\underset{\text{(A)}}{CH3}\phantom{}\phantom{.................}}
\ce{\underset{\text{Propan-2-amine(B)}}{CH3}}
\end{array}\]
\ce{H3C - CH = OH ->[\triangle][PBr3] H3C - CH - Br ->[NH3, Excess]H3C - CH - NH2}\\
|\phantom{......................}|\phantom{..........................}|\phantom{..}\\
\ce{\underset{\text{Isopropyl alcohol}}{CH3}\phantom{..............}}
\ce{\underset{\text{(A)}}{CH3}\phantom{}\phantom{.................}}
\ce{\underset{\text{Propan-2-amine(B)}}{CH3}}
\end{array}\]