chapter 14 Biomolecules Class 12 Chemistry Textbook Solution
3. Answer the following
iv. Give two evidences for presence of formyl group in glucose.
Answer:-
Glucose undergoes oxidation when exposed to bromine water, a mild oxidizing agent, resulting in the formation of a six-carbon monocarboxylic acid known as gluconic acid. This oxidation suggests that the carbonyl group in glucose exists in the form of a formyl group (-CHO).
The hemiacetal group present in the glucopyranose structure of glucose is a potential aldehyde, specifically a formyl group. This formyl group imparts reducing properties to glucose, causing it to yield positive results in tests such as the Tollen’s test or Fehling test.
chapter 14 Biomolecules Class 12 Chemistry Textbook Solution
page 321
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