Given: Current (\(I\)) = 0.8 ampere, Time (\(t\)) = 1 hour = 1 \times 60 \times 60 s = 3600 s To find: Number of moles of electrons passed through molten CaCl₂ Formulae: 1. Quantity of electricity passed = \[I(\text{A}) \times t(\text{s})\] 2. Number of moles of electrons passed = \(\frac{Q(\text{C})}{96500 \left(\frac{\text{C}}{\text{mol}\, e^-}\right)}\) Calculation: Using formula (i), Quantity of electricity passed = (\(I(\text{A}) \times t\(text{s}) = 0.8 \times 3600 \) (\= 2880 \text{ C}\) Using formula (ii), Number of moles of electrons passed: \[\frac{Q(\text{C})}{96500 \left(\frac{\text{C}}{\text{mol}\, e^-}\right)}\] \[= \frac{2880 \text{ C}}{96500 \left(\frac{\text{C}}{\text{mol}\, e^-}\right)} \] \[= 0.03 \text{ mol}\, e^-\] Number of moles of electrons passed through molten CaCl₂ is 0.03 mol \(e^-\).