Chapter 2  Solutions Class 12 Chemistry Maharashtra Board Textbook Solution

3. Answer the following.

vi. How molar mass of a solute is determined by osmotic pressure measurement?

Answer:- 1. For very dilute solutions, the osmotic pressure follows the equation: \[ \pi = \frac{n_2 RT}{V} \quad \ldots \text{(1)} \] 2. If the mass of solute in \(V\) liters of a solution is \(W_2\) and its molar mass is \(M_2\), then \(n_2 = \frac{W_2}{M_2}\). Substituting the value of \(n_2\) in equation (1), we get: \[ \pi = \frac{W_2 RT}{M_2 V} \] Therefore: \[ M_2 = \frac{W_2 RT}{\pi V} \] This formula can be used for the calculation of the molar mass of a nonionic solute (i.e., nonelectrolyte) by osmotic pressure measurement.

Chapter 2  Solutions Class 12 Chemistry Maharashtra Board Textbook Solution